2[(2y-1)+y]=5(y+3)

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Solution for 2[(2y-1)+y]=5(y+3) equation:


Simplifying
2[(2y + -1) + y] = 5(y + 3)

Reorder the terms:
2[(-1 + 2y) + y] = 5(y + 3)

Remove parenthesis around (-1 + 2y)
2[-1 + 2y + y] = 5(y + 3)

Combine like terms: 2y + y = 3y
2[-1 + 3y] = 5(y + 3)
[-1 * 2 + 3y * 2] = 5(y + 3)
[-2 + 6y] = 5(y + 3)

Reorder the terms:
-2 + 6y = 5(3 + y)
-2 + 6y = (3 * 5 + y * 5)
-2 + 6y = (15 + 5y)

Solving
-2 + 6y = 15 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
-2 + 6y + -5y = 15 + 5y + -5y

Combine like terms: 6y + -5y = 1y
-2 + 1y = 15 + 5y + -5y

Combine like terms: 5y + -5y = 0
-2 + 1y = 15 + 0
-2 + 1y = 15

Add '2' to each side of the equation.
-2 + 2 + 1y = 15 + 2

Combine like terms: -2 + 2 = 0
0 + 1y = 15 + 2
1y = 15 + 2

Combine like terms: 15 + 2 = 17
1y = 17

Divide each side by '1'.
y = 17

Simplifying
y = 17

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